Parmentier P.FRA () vs Siniakova K.CZE ()
predictions and statistics
12/11/2015 15:50
Limoges, surface: Hard
| Round | Match | Prob. in % | Tip | Games | FT | |
|---|---|---|---|---|---|---|
| R16 |
Parmentier P.(FRA) Siniakova K.(CZE) 12/11/2015 15:50
|
6
5
7
7
|
0 2
|
|||
All matches between both players
Parmentier P.
0
0%
Siniakova K.
3
100%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
MadridMadrid R64 |
07/05/2017 |
Siniakova K. Parmentier P. 07/05/2017
|
6
6
1
0
|
2 0
|
|
WimbledonWimbledon R128 |
28/06/2016 |
Parmentier P. Siniakova K. 28/06/2016
|
3
5
6
7
|
0 2
|
|
LimogesLimoges R16 |
12/11/2015 |
Parmentier P. Siniakova K. 12/11/2015
|
6
5
7
7
|
0 2
|
Parmentier P. performance on Hard
Win
70
40%
Lose
100
57%
Total matches: 174
Cancelled: 4
Siniakova K. performance on Hard
Win
116
43%
Lose
134
49%
Total matches: 272
Cancelled: 22
Last 6 matches Parmentier P.
Win
0
0%
Lose
6
100%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Roland GarrosRoland Ga.. R128 |
Parmentier P. Kudermetova V. 29/09/2020
|
2
3
6
6
|
0 2
|
|
StrasbourgStrasbourg R32 |
Linette M. Parmentier P. 21/09/2020
|
6
6
4
3
|
2 0
|
|
Australian OpenAustralia.. R128 |
Wang Q. Parmentier P. 21/01/2020
|
7
6
6
3
|
2 0
|
|
LuxembourgLuxembourg R32 |
Parmentier P. Cirstea S. 15/10/2019
|
3
4
6
6
|
0 2
|
|
US OpenUS Open R128 |
Parmentier P. Pavlyuchenkova A. 27/08/2019
|
1
6
6
7
|
0 2
|
|
PalermoPalermo R32 |
Badosa G. P. Parmentier P. 22/07/2019
|
6
7
4
6
|
2 0
|
Last 6 matches Siniakova K.
Win
3
50%
Lose
3
50%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
MiamiMiami R64 |
Jabeur O. Siniakova K. 20/03/2025
|
6
7
4
6
|
2 0
|
|
MiamiMiami R128 |
Yuan Y. Siniakova K. 18/03/2025
|
2
6
6
6
2
7
|
1 2
|
|
Indian WellsIndian We.. R32 |
Muchova K. Siniakova K. 09/03/2025
|
7
6
5
1
|
2 0
|
|
Indian WellsIndian We.. R64 |
Siniakova K. Noskova L. 07/03/2025
|
6
6
2
2
|
2 0
|
|
Indian WellsIndian We.. R128 |
Carle M. Siniakova K. 06/03/2025
|
2
1
6
6
|
0 2
|
|
DubaiDubai R64 |
Siniakova K. Kostyuk M. 17/02/2025
|
3
4
6
6
|
0 2
|