Parmentier P.FRA () vs Siniakova K.CZE ()
predictions and statistics
12/11/2015 16:50
Limoges, surface: Hard
| Round | Match | Prob. in % | Tip | Games | FT | |
|---|---|---|---|---|---|---|
| R16 |
Parmentier P.(FRA) Siniakova K.(CZE) 12/11/2015 16:50
|
6
5
7
7
|
0 2
|
|||
All matches between both players
Parmentier P.
0
0%
Siniakova K.
3
100%
| TournamentTour. | Date | Match | Games | FT |
|---|---|---|---|---|
|
MadridMadrid R64 |
07/05/2017 |
Siniakova K. Parmentier P. 07/05/2017
|
6
6
1
0
|
2 0
|
|
WimbledonWimbledon R128 |
28/06/2016 |
Parmentier P. Siniakova K. 28/06/2016
|
3
5
6
7
|
0 2
|
|
LimogesLimoges R16 |
12/11/2015 |
Parmentier P. Siniakova K. 12/11/2015
|
6
5
7
7
|
0 2
|
Parmentier P. performance on Hard
Win
70
40%
Lose
100
57%
Total matches: 174
Cancelled: 4
Siniakova K. performance on Hard
Win
110
43%
Lose
129
50%
Total matches: 258
Cancelled: 19
Last 6 matches Parmentier P.
Win
0
0%
Lose
6
100%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
Roland GarrosRoland Ga.. R128 |
Parmentier P. Kudermetova V. 29/09/2020
|
2
3
6
6
|
0 2
|
|
StrasbourgStrasbourg R32 |
Linette M. Parmentier P. 21/09/2020
|
6
6
4
3
|
2 0
|
|
Australian OpenAustralia.. R128 |
Wang Q. Parmentier P. 21/01/2020
|
7
6
6
3
|
2 0
|
|
LuxembourgLuxembourg R32 |
Parmentier P. Cirstea S. 15/10/2019
|
3
4
6
6
|
0 2
|
|
US OpenUS Open R128 |
Parmentier P. Pavlyuchenkova A. 27/08/2019
|
1
6
6
7
|
0 2
|
|
PalermoPalermo R32 |
Badosa G. P. Parmentier P. 22/07/2019
|
6
7
4
6
|
2 0
|
Last 6 matches Siniakova K.
Win
4
67%
Lose
1
17%
| Tour. | Match | Games | FT |
|---|---|---|---|
|
GuangzhouGuangzhou SF |
Siniakova K. Danilovic O. 26/10/2024
|
6
4
3
4
6
4
|
Ret |
|
GuangzhouGuangzhou QF |
Siniakova K. Pera B. 25/10/2024
|
6
7
4
5
|
2 0
|
|
GuangzhouGuangzhou R16 |
Siniakova K. Parks A. 24/10/2024
|
6
6
1
4
|
2 0
|
|
GuangzhouGuangzhou R32 |
Siniakova K. Martic P. 22/10/2024
|
6
6
2
1
|
2 0
|
|
NingboNingbo R16 |
Kasatkina D. Siniakova K. 16/10/2024
|
1
6
6
6
3
2
|
2 1
|
|
NingboNingbo R32 |
Siniakova K. Linette M. 15/10/2024
|
6
6
2
4
|
2 0
|